Optimal. Leaf size=315 \[ \frac{b (e x)^{m+1} \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b x^n}{a}\right ) (A b (a d (m-3 n+1)-b c (m-n+1))+a B (b c (m+1)-a d (m-2 n+1)))}{a^2 e (m+1) n (b c-a d)^3}-\frac{d (e x)^{m+1} \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{d x^n}{c}\right ) (a d (B c (m+1)-A d (m-n+1))+b c (A d (m-3 n+1)-B c (m-2 n+1)))}{c^2 e (m+1) n (b c-a d)^3}+\frac{d (e x)^{m+1} (a A d-2 a B c+A b c)}{a c e n (b c-a d)^2 \left (c+d x^n\right )}+\frac{(e x)^{m+1} (A b-a B)}{a e n (b c-a d) \left (a+b x^n\right ) \left (c+d x^n\right )} \]
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Rubi [A] time = 1.09656, antiderivative size = 315, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 3, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.097, Rules used = {595, 597, 364} \[ \frac{b (e x)^{m+1} \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b x^n}{a}\right ) (A b (a d (m-3 n+1)-b c (m-n+1))+a B (b c (m+1)-a d (m-2 n+1)))}{a^2 e (m+1) n (b c-a d)^3}-\frac{d (e x)^{m+1} \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{d x^n}{c}\right ) (a d (B c (m+1)-A d (m-n+1))+b c (A d (m-3 n+1)-B c (m-2 n+1)))}{c^2 e (m+1) n (b c-a d)^3}+\frac{d (e x)^{m+1} (a A d-2 a B c+A b c)}{a c e n (b c-a d)^2 \left (c+d x^n\right )}+\frac{(e x)^{m+1} (A b-a B)}{a e n (b c-a d) \left (a+b x^n\right ) \left (c+d x^n\right )} \]
Antiderivative was successfully verified.
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Rule 595
Rule 597
Rule 364
Rubi steps
\begin{align*} \int \frac{(e x)^m \left (A+B x^n\right )}{\left (a+b x^n\right )^2 \left (c+d x^n\right )^2} \, dx &=\frac{(A b-a B) (e x)^{1+m}}{a (b c-a d) e n \left (a+b x^n\right ) \left (c+d x^n\right )}-\frac{\int \frac{(e x)^m \left (-a B c (1+m)+A b c (1+m-n)+a A d n+(A b-a B) d (1+m-2 n) x^n\right )}{\left (a+b x^n\right ) \left (c+d x^n\right )^2} \, dx}{a (b c-a d) n}\\ &=\frac{d (A b c-2 a B c+a A d) (e x)^{1+m}}{a c (b c-a d)^2 e n \left (c+d x^n\right )}+\frac{(A b-a B) (e x)^{1+m}}{a (b c-a d) e n \left (a+b x^n\right ) \left (c+d x^n\right )}-\frac{\int \frac{(e x)^m \left (-n \left (a B c (b c+a d) (1+m)-A \left (b^2 c^2 (1+m-n)+a^2 d^2 (1+m-n)+2 a b c d n\right )\right )+b d (A b c-2 a B c+a A d) (1+m-n) n x^n\right )}{\left (a+b x^n\right ) \left (c+d x^n\right )} \, dx}{a c (b c-a d)^2 n^2}\\ &=\frac{d (A b c-2 a B c+a A d) (e x)^{1+m}}{a c (b c-a d)^2 e n \left (c+d x^n\right )}+\frac{(A b-a B) (e x)^{1+m}}{a (b c-a d) e n \left (a+b x^n\right ) \left (c+d x^n\right )}-\frac{\int \left (\frac{b c (-a B (b c (1+m)-a d (1+m-2 n))-A b (a d (1+m-3 n)-b c (1+m-n))) n (e x)^m}{(b c-a d) \left (a+b x^n\right )}+\frac{a d (b c (A d (1+m-3 n)-B c (1+m-2 n))+a d (B c (1+m)-A d (1+m-n))) n (e x)^m}{(b c-a d) \left (c+d x^n\right )}\right ) \, dx}{a c (b c-a d)^2 n^2}\\ &=\frac{d (A b c-2 a B c+a A d) (e x)^{1+m}}{a c (b c-a d)^2 e n \left (c+d x^n\right )}+\frac{(A b-a B) (e x)^{1+m}}{a (b c-a d) e n \left (a+b x^n\right ) \left (c+d x^n\right )}+\frac{(b (a B (b c (1+m)-a d (1+m-2 n))+A b (a d (1+m-3 n)-b c (1+m-n)))) \int \frac{(e x)^m}{a+b x^n} \, dx}{a (b c-a d)^3 n}-\frac{(d (b c (A d (1+m-3 n)-B c (1+m-2 n))+a d (B c (1+m)-A d (1+m-n)))) \int \frac{(e x)^m}{c+d x^n} \, dx}{c (b c-a d)^3 n}\\ &=\frac{d (A b c-2 a B c+a A d) (e x)^{1+m}}{a c (b c-a d)^2 e n \left (c+d x^n\right )}+\frac{(A b-a B) (e x)^{1+m}}{a (b c-a d) e n \left (a+b x^n\right ) \left (c+d x^n\right )}+\frac{b (a B (b c (1+m)-a d (1+m-2 n))+A b (a d (1+m-3 n)-b c (1+m-n))) (e x)^{1+m} \, _2F_1\left (1,\frac{1+m}{n};\frac{1+m+n}{n};-\frac{b x^n}{a}\right )}{a^2 (b c-a d)^3 e (1+m) n}-\frac{d (b c (A d (1+m-3 n)-B c (1+m-2 n))+a d (B c (1+m)-A d (1+m-n))) (e x)^{1+m} \, _2F_1\left (1,\frac{1+m}{n};\frac{1+m+n}{n};-\frac{d x^n}{c}\right )}{c^2 (b c-a d)^3 e (1+m) n}\\ \end{align*}
Mathematica [A] time = 0.316594, size = 209, normalized size = 0.66 \[ \frac{x (e x)^m \left (\frac{b (a B-A b) (a d-b c) \, _2F_1\left (2,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b x^n}{a}\right )}{a^2}-\frac{d (b c-a d) (B c-A d) \, _2F_1\left (2,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{d x^n}{c}\right )}{c^2}+\frac{b (a B d-2 A b d+b B c) \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{b x^n}{a}\right )}{a}-\frac{d (a B d-2 A b d+b B c) \, _2F_1\left (1,\frac{m+1}{n};\frac{m+n+1}{n};-\frac{d x^n}{c}\right )}{c}\right )}{(m+1) (b c-a d)^3} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.716, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( ex \right ) ^{m} \left ( A+B{x}^{n} \right ) }{ \left ( a+b{x}^{n} \right ) ^{2} \left ( c+d{x}^{n} \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\left ({\left (b^{3} c e^{m}{\left (m - n + 1\right )} - a b^{2} d e^{m}{\left (m - 3 \, n + 1\right )}\right )} A +{\left (a^{2} b d e^{m}{\left (m - 2 \, n + 1\right )} - a b^{2} c e^{m}{\left (m + 1\right )}\right )} B\right )} \int -\frac{x^{m}}{a^{2} b^{3} c^{3} n - 3 \, a^{3} b^{2} c^{2} d n + 3 \, a^{4} b c d^{2} n - a^{5} d^{3} n +{\left (a b^{4} c^{3} n - 3 \, a^{2} b^{3} c^{2} d n + 3 \, a^{3} b^{2} c d^{2} n - a^{4} b d^{3} n\right )} x^{n}}\,{d x} -{\left ({\left (a d^{3} e^{m}{\left (m - n + 1\right )} - b c d^{2} e^{m}{\left (m - 3 \, n + 1\right )}\right )} A +{\left (b c^{2} d e^{m}{\left (m - 2 \, n + 1\right )} - a c d^{2} e^{m}{\left (m + 1\right )}\right )} B\right )} \int -\frac{x^{m}}{b^{3} c^{5} n - 3 \, a b^{2} c^{4} d n + 3 \, a^{2} b c^{3} d^{2} n - a^{3} c^{2} d^{3} n +{\left (b^{3} c^{4} d n - 3 \, a b^{2} c^{3} d^{2} n + 3 \, a^{2} b c^{2} d^{3} n - a^{3} c d^{4} n\right )} x^{n}}\,{d x} + \frac{{\left ({\left (b^{2} c^{2} e^{m} + a^{2} d^{2} e^{m}\right )} A -{\left (a b c^{2} e^{m} + a^{2} c d e^{m}\right )} B\right )} x x^{m} -{\left (2 \, B a b c d e^{m} -{\left (b^{2} c d e^{m} + a b d^{2} e^{m}\right )} A\right )} x e^{\left (m \log \left (x\right ) + n \log \left (x\right )\right )}}{a^{2} b^{2} c^{4} n - 2 \, a^{3} b c^{3} d n + a^{4} c^{2} d^{2} n +{\left (a b^{3} c^{3} d n - 2 \, a^{2} b^{2} c^{2} d^{2} n + a^{3} b c d^{3} n\right )} x^{2 \, n} +{\left (a b^{3} c^{4} n - a^{2} b^{2} c^{3} d n - a^{3} b c^{2} d^{2} n + a^{4} c d^{3} n\right )} x^{n}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B x^{n} + A\right )} \left (e x\right )^{m}}{b^{2} d^{2} x^{4 \, n} + a^{2} c^{2} + 2 \,{\left (b^{2} c d + a b d^{2}\right )} x^{3 \, n} +{\left (b^{2} c^{2} + 4 \, a b c d + a^{2} d^{2}\right )} x^{2 \, n} + 2 \,{\left (a b c^{2} + a^{2} c d\right )} x^{n}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{n} + A\right )} \left (e x\right )^{m}}{{\left (b x^{n} + a\right )}^{2}{\left (d x^{n} + c\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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